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If you weren't aware, the ISS is making a number of bright, high-altitude passes over the southern UK this week. (Predictions for my location are here.) So I thought it would be fun to try to photograph it, with ordinary camera equipment rather than a telescope or anything.
But I've been struggling and I think some of my assumptions / calculations must be wrong. I'd be grateful if somebody could look through my reasoning and spot the error.
How big is it?
The ISS measures about 109m by 73m (reference) and its orbital altitide is 413 to 418 km (reference).
I'll be photographing it with my trusty old Canon 40D, which has an APS-C sensor measuring 14.8mm across.
The simple rule for telephoto subjects is that, to fill the frame, subject size / subject distance = sensor size / focal length. So in order to fill the frame I need a lens with a focal length of 14.8mm x 418km / 109m, which comes to 56,756mm.
OK, obviously I was never hoping to fill the frame. Say I use a 300mm f/2.8 with a 2x extender. I can use that hand-held, which will be handy for acquiring and following a moving object. That gives me 600mm of focal length. So instead of the ISS filling the whole 2592 pixels of the sensor, it will cover 2592 x 600 / 56756 = 27 pixels.
What does 27 pixels look like? Well, to get a feel for it I've used a NASA image (here), scaled it down to 27 pixels across, and then enlarged it by 10x to make it easier to see. Here it is:
I'd be pretty happy if I could do that.
How fast is it moving?
The orbital velocity of the ISS is about 7.66 km/sec according to Wikipedia (reference). I'll be photographing it with each pixel corresponding to 109 / 27 = 4m. So in one second it will cover the equivalent of 7660 / 4 = 1915 pixels.
This gives me two conclusions. Firstly, it will move across the frame in under 2 seconds, so trying to shoot it hand-held sounds like it might be a good idea. And secondly, if I can maintain a shutter speed of 1/2000th or faster, I should be able to freeze it at the pixel level.
How bright is it?
By definition the ISS is only visible if it is in sunlight. And there are no clouds up there, and no haze, so it's going to be bright sunlight. Hence it seems to me that the Sunny-16 rule ought to be applicable.
So, for a shutter speed of 1/2000th, I need f/16 and ISO 2000. Or if I open up the aperture by 3 stops, I get f/5.6 and ISO 250. And let's say I want a extra stop of shutter speed to make sure I don't blur it. So I have 1/4000th at f/5.6 and ISO 500. That sounds achievable.
Before I post any of my results, can anyone spot a flaw in any of my reasoning?
But I've been struggling and I think some of my assumptions / calculations must be wrong. I'd be grateful if somebody could look through my reasoning and spot the error.
How big is it?
The ISS measures about 109m by 73m (reference) and its orbital altitide is 413 to 418 km (reference).
I'll be photographing it with my trusty old Canon 40D, which has an APS-C sensor measuring 14.8mm across.
The simple rule for telephoto subjects is that, to fill the frame, subject size / subject distance = sensor size / focal length. So in order to fill the frame I need a lens with a focal length of 14.8mm x 418km / 109m, which comes to 56,756mm.
OK, obviously I was never hoping to fill the frame. Say I use a 300mm f/2.8 with a 2x extender. I can use that hand-held, which will be handy for acquiring and following a moving object. That gives me 600mm of focal length. So instead of the ISS filling the whole 2592 pixels of the sensor, it will cover 2592 x 600 / 56756 = 27 pixels.
What does 27 pixels look like? Well, to get a feel for it I've used a NASA image (here), scaled it down to 27 pixels across, and then enlarged it by 10x to make it easier to see. Here it is:
![ISS-1.jpg](/proxy.php?image=http%3A%2F%2Fwww.talkphotography.co.uk%2Fgallery%2Fdata%2F1308%2FISS-1.jpg&hash=d8b9c89aa992dc5bbc440493a27c8b3c)
I'd be pretty happy if I could do that.
How fast is it moving?
The orbital velocity of the ISS is about 7.66 km/sec according to Wikipedia (reference). I'll be photographing it with each pixel corresponding to 109 / 27 = 4m. So in one second it will cover the equivalent of 7660 / 4 = 1915 pixels.
This gives me two conclusions. Firstly, it will move across the frame in under 2 seconds, so trying to shoot it hand-held sounds like it might be a good idea. And secondly, if I can maintain a shutter speed of 1/2000th or faster, I should be able to freeze it at the pixel level.
How bright is it?
By definition the ISS is only visible if it is in sunlight. And there are no clouds up there, and no haze, so it's going to be bright sunlight. Hence it seems to me that the Sunny-16 rule ought to be applicable.
So, for a shutter speed of 1/2000th, I need f/16 and ISO 2000. Or if I open up the aperture by 3 stops, I get f/5.6 and ISO 250. And let's say I want a extra stop of shutter speed to make sure I don't blur it. So I have 1/4000th at f/5.6 and ISO 500. That sounds achievable.
Before I post any of my results, can anyone spot a flaw in any of my reasoning?