1. BADGER.BRAD

    BADGER.BRAD

    Messages:
    400
    Name:
    BRAD
    Edit My Images:
    Yes
    I have been messing today with my Kodak Pixpro, as it tends to slightly over expose in bright light I've took to using exposure compensation in Aperture priority mode if I think it is too bright ranging from -0.3 and -0.7Ev which seems to help but I wondered how would one stop compare to this EV is this -0.3 Ev just roughly a third of a stop or have I got this totally wrong !
     
  2. toohuge

    toohuge

    Messages:
    98
    Edit My Images:
    Yes
  3. Nawty

    Nawty

    Messages:
    6,109
    Name:
    Ned
    Edit My Images:
    Yes
    Ev = exposure value = f stop.

    Same thing.
     
  4. BADGER.BRAD

    BADGER.BRAD

    Messages:
    400
    Name:
    BRAD
    Edit My Images:
    Yes
    Thanks everyone I wasn't sure !
     
  5. Graham W

    Graham W

    Messages:
    1,755
    Name:
    Graham
    Edit My Images:
    Yes
    If anyone wondered where the strange f numbers come from it's back to the good old inverse square law.
    The aperture doubles in size with each full stop (step) and the f number is the square root of that doubling.

    f number

    1 √ = 1

    2 √ = 1.4

    4 √ = 2

    8 √ = 2.8

    16 √ = 4

    32 √ = 5.6

    64 √ = 8

    128 √ = 11

    256 √ = 16

    512 √ = 22

    1024 √ = 32

    And so on.
     
    Phil V likes this.

Share This Page

  1. This site uses cookies to help personalise content, tailor your experience and to keep you logged in if you register.
    By continuing to use this site, you are consenting to our use of cookies.
    Dismiss Notice